あなたはbashのソリューションの下に試すことができます - スクリプトの
猫
1 2017-02-22T11:09:41.000Z
2 2017-02-23T11:09:41.000Z
3 2017-02-24T11:09:41.000Z
4 2017-02-25T11:09:41.000Z
5 2017-02-26T11:09:41.000Z
cat ./time.sh
#!/bin/bash
d="2017-02-21T11:09:41.000Z"
b="2017-02-23T11:09:41.000Z"
USERTIME1=`awk -F'[T]|[-]|[:]|[.]' '{datetime=mktime($1 " "$2 " " $3 " " $4 " " $5 " " $6); print datetime}' <<< $d`
USERTIME2=`awk -F'[T]|[-]|[:]|[.]' '{datetime=mktime($1 " "$2 " " $3 " " $4 " " $5 " " $6); print datetime}' <<< $b`
for i in `cat time.txt|awk '{print $2}'`
do
var=`awk 'BEGIN{FS="[T]|[-]|[:]|[.]"} {print mktime($1 " "$2 " " $3 " " $4 " " $5 " " $6)}' <<< $i`
var1=`expr $var - 21600`
if [ $var1 -ge $USERTIME1 ] && [ $var1 -le $USERTIME2 ]
then
echo "$i"
fi
done
time.txt出力を:
./time.sh
2017-02-22T11:09:41.000Z
2017-02-23T11:09:41.000Z
私はこれをawkだけで解決しようとしていましたが、誰かが助けてくれれば成功しませんでした。ここにコードはありますか?
### 1:11 AM Friday, Eastern Time (ET) is
### 6:11 AM Friday, Coordinated Universal Time (UTC)
### UTC to EST is 6 hour of difference means (-21600)
BEGIN{FS="[T]|[-]|[:]|[.]";d="2017-02-25T11:09:41.000Z";b="2017-02-23T11:09:41.000Z"}
{
USERTIME1=(substr(d,0,4) " " substr(d,6,2) " "substr(d,9,2) " " substr(d,12,2) " " substr(d,15,2) " "substr(d,18,2) " " substr(d,21,2))
USERTIME2=(substr(b,0,4) " " substr(b,6,2) " "substr(b,9,2) " " substr(b,12,2) " " substr(b,15,2) " "substr(b,18,2) " " substr(b,21,2))
UTCTIME=($1 " "$2 " " $3 " " $4 " " $5 " " $6)
ESTTIME=(UTCTIME-21600)
if((mktime(ESTTIME) >= mktime(USERTIME1)) && mktime((ESTTIME) <= mktime(USERTIME2))
print
}
POSIX awkまたはgawk? gawkは標準的な行であり、時間関数を持っています。 – dawg
上記の問題を解決するもの(awk、gawkまたはperl) –