Oracle SQL。 2列

Question

私はテーブルを持っているに基づいて数：

JIRA_KEY DATACENTER STATUS 
    1   US  CLOSED 
    2   EM  CLOSED 
    3   AP  CLOSED 
    4   US  CLOSED 
    5   EM  IN PROGRESS 
    6   AP  CANCELLED 
    7   US  IN PROGRESS 
    8   US  CANCELLED 
    9   AP  CANCELLED 
10   AP  IN PROGRESS 

予想される出力：

Datacenter TotalJiras Closed InProgress Cancelled 
EMEA   2  1  1   0 
APAC   4  1  1   2 
AMERICA  4  2  1   1 

私は、ビューを作成してみました：予想通り

create or replace view VW_JIRA_STATUS_BK AS 
SELECT count(JIRA_KEY) JIRA , 
    decode (substr(data_center,1,2),'EM', 'EMEA', 'AP', 'APAC', 'US', 'AMERICA') as REGION, 
    status 
from hw_jira_status 
group by data_center , status; 

select * from VW_JIRA_STATUS_BK 

は結果を表示しません。

ご協力いただければ幸いです。

Answer 1

あなたはCASE、各結果列のための1つを使用して条件付き集計必要があります：それはとにかく2つの文字だ場合、なぜあなたはdata_centerにSUBSTRを適用ん

create or replace view VW_JIRA_STATUS_BK AS 
SELECT 
    decode (substr(data_center,1,2),'EM', 'EMEA', 'AP', 'APAC', 'US', 'AMERICA') as REGION, 
    count(JIRA_KEY) AS TotalJiras, 
    COUNT(CASE WHEN Status = 'CLOSED' THEN 1 END) AS Closed, 
    COUNT(CASE WHEN Status = 'IN PROGRESS' THEN 1 END) AS InProgress, 
    COUNT(CASE WHEN Status = 'CANCELLED' THEN 1 END) AS Cancelled 
from hw_jira_status 
group by data_center; -- don't group by "Status" 

を？

ところで、私は標準SQLのCASE Oracleの廃止予定DECODEオーバーをpefer：ルールBY

CASE data_center 
    WHEN 'EM' THEN 'EMEA' 
    WHEN 'AP' THEN 'APAC' 
    WHEN 'US' THEN 'AMERICA' 
END as REGION,