PHPでスコープ解決演算子を使用してget_class（）を使用する方法？

Question

<?php 
class X { 
    function foo() { 

     echo "Class Name:".get_class($this)."<br>"; //it displays Y... :) 
     echo get_class($this)::$public_var; //not working 
     echo Y::$public_var; //works 
     Y::y_method(); //works 
     get_class($this)::y_method(); //not working 

     $classname = get_class($this); 
     $classname::y_method(); // again not working.. :( 
    } 

    function bar() { 
     $this->foo(); 
    } 
} 

class Y extends X { 

    public static $public_var = "Variable of Y Class"; 
    public function y_method() 
    { 
     echo "Y class method"; 
    } 
} 

$y = new Y(); 
$y->bar(); 

?> 
my only question is how to get access members of y class only with dynamically providing class name without changing current structure. 

Answer 1

あなたはget_called_class()

class X { 
    function foo() { 
    $that = get_called_class(); 
     echo $that::$private_var; 
     echo $that::y_method(); 
    } 

    function bar() { 
     $this->foo(); 
    } 
} 

class Y extends X { 

    public static $private_var = "Variable of Y Class"; 
    public function y_method() 
    { 
     echo "Y class method"; 
    } 
} 

$y = new Y(); 
$y->bar();