別の列が同じでない異なる行を数えよう

Question

CODEが区別されないNUMのカウント方法を知りたいですか？

したがって、数は2つになります。

CODE NUM 
T1 1001 
T1 1001 
T1 1001 
T2 1002 
T2 1002 
T3 1003 
T3 1003 
T4 1003 
T5 1004 
T5 1004 
T5 1004 
T6 1005 
T7 1005 
T7 1005 

Answer 1

Try Below code : 

SELECT NUM , COUNT(*) 
FROM #table 
GROUP BY NUM 
HAVING COUNT(DISTINCT CODE) > 1 

Answer 2

これを試してください：あなたの予想出力は何

Select count(*) 
From (
    Select num 
    From t 
    Group by num 
    Having count(distinct code) > 1 
) t; 

Answer 3

Create table #Tempt 
(
    CODE varchar(50), 
    NUM int 

) 

Delete From #Tempt 

insert into #Tempt Values('T1',1001) 
insert into #Tempt Values('T1',1001) 
insert into #Tempt Values('T1',1001) 
insert into #Tempt Values('T2',1002) 
insert into #Tempt Values('T2',1002) 
insert into #Tempt Values('T2',1002) 
insert into #Tempt Values('T3',1003) 
insert into #Tempt Values('T3',1003) 
insert into #Tempt Values('T4',1004) 
insert into #Tempt Values('T5',1005) 
insert into #Tempt Values('T5',1005) 
insert into #Tempt Values('T6',1006) 
insert into #Tempt Values('T7',1007) 
insert into #Tempt Values('T7',1007) 

Select Count(*) as TotalCount From (Select Code,Num , 
(Select Count(*) From #Tempt Where code = t.code) as CountCode 
from #Tempt as t) as v Where CountCode=1