3つの勘定（）の合計を取得するにはどうすればよいですか？ここ

Question

は私のクエリです：

SELECT (SELECT COUNT(`id`) FROM `table1` WHERE `id` = '1') AS `count1`, 
(SELECT COUNT(`id`) FROM `table2` WHERE `id` = '1') AS `count2`, 
(SELECT COUNT(`id`) FROM `table3` WHERE `id` = '1') AS `count3` 

にはどうすればcount1, count2, count3の合計を得ることができますか？

上記のというクエリには何らかの方法がありますか？

Answer 1

単に値を一緒に追加してください：

SELECT (SELECT COUNT(`id`) FROM `table1` WHERE `id` = '1') + 
     (SELECT COUNT(`id`) FROM `table2` WHERE `id` = '1') + 
     (SELECT COUNT(`id`) FROM `table3` WHERE `id` = '1') AS `sum` ...