のmysql：リクエスト

Question

からのグループの結果は、私のSQL要求は私を与える：

 SELECT 
     sf_guard_user.id, sf_guard_user.username, sf_guard_user.avatar_time, fromid, toid,sum(chatMessage.fromidlu) - sum(chatMessage.toidlu) as nonlus 
     FROM chatMessage, sf_guard_user 
     WHERE (chatMessage.fromid = sf_guard_user.id AND toid=16595 AND toidhidden=0) OR (chatMessage.toid = sf_guard_user.id AND fromid=16595 AND fromidhidden=0) 
     GROUP by fromid 

私はこの結果に別のSQLを適用したいので、最終的な結果は、「nonlus」

に合計を作るています

SELECT id, username, avatar_time, fromid, toid, sum(nonlus) FROM 
**this request** 
order by id 

私は

SELECT id, username, avatar_time, fromid, toid, sum(nonlus) FROM (
      SELECT 
      sf_guard_user.id, sf_guard_user.username, sf_guard_user.avatar_time, fromid, toid,sum(chatMessage.fromidlu) - sum(chatMessage.toidlu) as nonlus 
      FROM chatMessage, sf_guard_user 
      WHERE (chatMessage.fromid = sf_guard_user.id AND toid=16595 AND toidhidden=0) OR (chatMessage.toid = sf_guard_user.id AND fromid=16595 AND fromidhidden=0) 
      GROUP by fromid) 
Group by id 

を試してみました

しかし、エラーが

すべての派生テーブルは、あなただけのインナーselectにエイリアスを割り当てる必要が

Answer 1

独自の別名を持っている必要があります取得するには、次のことを試してください。

SELECT id, username, avatar_time, fromid, toid, sum(nonlus) FROM (
      SELECT 
      sf_guard_user.id as id, sf_guard_user.username as username, sf_guard_user.avatar_time as avatar_time, fromid, toid, sum(chatMessage.fromidlu) - sum(chatMessage.toidlu) as nonlus 
      FROM chatMessage, sf_guard_user 
      WHERE (chatMessage.fromid = sf_guard_user.id AND toid=16595 AND toidhidden=0) OR (chatMessage.toid = sf_guard_user.id AND fromid=16595 AND fromidhidden=0) 
      GROUP by fromid) a 
Group by a.id