グループSQLステートメント - 都市が5つ以上ある国を取得する

Question

5つ以上の都市を持つ国を引き抜こうとしています。

テーブル：

市city_id, city, country_id, last_update

国country_id, country, last_update

私はこれが考え出し得るために非常に近いと思うが、私はかなりありませんよ。すべてのポインタ？

SELECT DISTINCT country 
FROM country C, city O 
WHERE O.country_id = C.country_id AND O.country_id 
IN (SELECT country_id FROM city group by country_id having count(country_id) > 5); 

Answer 1

select country 
from country inner join city on city.country_id = country.country_id 
group by country 
having count(distinct city) > 5 

Answer 2

Use the below query.. 

    SELECT country 
    FROM country C 
    JOIN city O 
    ON O.country_id = C.country_id 
    GROUP BY country 
    HAVING count(distinct O.city)>5 

Answer 3

あなたは以下のクエリはあなたの条件のために働くこの

select countryid, count(distinct city_id) from country c join city ct c.country_id=ct.country_id 
group by countryid 
having count(distinct city_id) > 5 

Answer 4

SELECT DISTINCT 
     country 
FROM country C 
WHERE EXISTS (SELECT COUNT(DISTINCT city_id) 
       FROM city CITY 
       WHERE CITY.country_id = C.country_id 
       GROUP BY CITY.country_id 
       HAVING COUNT(DISTINCT city_id) > 5); 

Answer 5

のように試すことができます。

SELECT C.country 
    FROM country C 
    INNER JOIN 
      city O 
     ON O.country_id = C.country_id 
    GROUP BY C.country 
    HAVING count(distinct O.city)>5;