私のIDはelse if条件で返されません

Question

私のIDはelse if条件で返されません。 「位置0に行がありません」ということを示しています。

USE [ctsdev] 
    GO 

    SET ANSI_NULLS ON 
    GO 

    SET QUOTED_IDENTIFIER ON 
    GO 

    alter PROCEDURE [dbo].[usp_incen] 
    (     

    @ConsultantName varchar(50) ,      
    @ClientName varchar(50) ,   
    @StartDate varchar(50),  
    @PositionName varchar(20) ,  
    @Location varchar(20) ,   
    @Job_Status varchar (20),       
    @BenchMarketing varchar(1) ,      
    @Placement varchar(1),  
    @CompanyName varchar(20),   
    @Durations varchar(20),    
    @DurationofProject varchar(10), 
    @Last_Updated_Date nvarchar(50), 
    @Rec_Name varchar(50), 
    @id int output 
    )  
    AS     
    BEGIN  

    SET NOCOUNT ON 

    /* checking whether the row with same session name and some id and updated date with remaining every fields as NULL exists*/ 

    if (SELECT COUNT(*) as cnt from tbl_Empincentivenew1 WHERE 
    id <> '' AND 
    Rec_Name = @Rec_Name and 
    Last_Updated_Date <> '' and 
    ConsultantName IS NULL and 
    ClientName IS NULL and 
    DurationofProject IS NULL and 
    Durations IS NULL and 
    StartDate IS NULL and 
    Location IS NULL and 
    BenchMarketing IS NULL and 
    Placement IS NULL and 
    CompanyName IS NULL)=0 



     BEGIN 

     /*if not then id field,recruitername and updated date is inserted*/ 

     INSERT INTO [tbl_Empincentivenew1](ConsultantName,ClientName,PositionName,CompanyName,Location,DurationofProject,Durations,BenchMarketing,Placement,Job_Status,Last_Updated_Date,StartDate,Rec_Name)      
    OUTPUT INSERTED.id 
    values(NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,NULL,@Last_Updated_Date,NULL,@Rec_Name) 

    SET @id=SCOPE_IDENTITY() 
    RETURN @id /*that id is returned to the front end*/ 
     ENd 
     /*if the id with rec name,updated date with remaining all fiels null exist return that particular id to front end*/ 
    ELSe if(SELECT COUNT(*) as cnt from tbl_Empincentivenew1 WHERE 
    id <> '' AND 
    Rec_Name = @Rec_Name and 
    Last_Updated_Date <> '' and 
    ConsultantName IS NULL and 
    ClientName IS NULL and 
    DurationofProject IS NULL and 
    Durations IS NULL and 
    StartDate IS NULL and 
    Location IS NULL and 
    BenchMarketing IS NULL and 
    Placement IS NULL and 
    CompanyName IS NULL)=1 


     BEGIN 
    SET @id=SCOPE_IDENTITY() /*return that existing id,instead for again inserting null values*/ 
    RETURN @id 
    END    

     END 

    GO 

これは、id値は、同じユーザーログインが彼が新しいヌルレコードを追加することは許可されていませんが、そのヌルレコードのIDが戻っていないとき二度目に挿入なっている最初のブロックのために私のコードです。

Answer 1

SCOPE_IDENTITY()最後に生成されたIDを返します。 ELSEブランチでは、新しいレコードを作成していないので、SCOPE_IDENTITY()はNULLのままです。

あなたELSE文は次のようになります

ELSE 
    SELECT @id = id 
    FROM tbl_Empincentivenew1 
    WHERE 
     Rec_Name = @Rec_Name and 
     Last_Updated_Date <> '' and 
     ConsultantName IS NULL and 
     ClientName IS NULL and 
     DurationofProject IS NULL and 
     Durations IS NULL and 
     StartDate IS NULL and 
     Location IS NULL and 
     BenchMarketing IS NULL and 
     Placement IS NULL and 
     CompanyName IS NULL 

@idはまだNULLであれば、私は最初、このSELECTを実行しますが - INSERTを実行し、@id = SCOPE_IDENTITY()を返します。