連合結果の除算

Question

2つのselectステートメントの結果を分割し、合計を含めることは可能ですか？

望ましい結果 Required Results

各カウントから1つの結果だけでは私の現在のコード

select sum(U.Orders) as sumtotal 
from 
(
    select distinct count(p.PACKSLIP) as Orders 
    from PICKHEAD as p 
    where DATE_REQD = '2017-04-19' 

    union 

    select distinct count(s.PACKSLIP) as Orders 
    from SHIPHIST as s 
    where DATE_REQD = '2017-04-19' 
) AS U 

Answer 1

私が正しくあなたを理解している場合、あなたはそれ

select sum(U.OrderList) + sum(U.Shiplist) as totalSalesOrder,sum(U.OrderList)/ (sum(U.Shiplist)+sum(U.OrderList)) * 100 as TotalComlpetionPercentage 
from 
(
    select distinct count(p.PACKSLIP) as OrderList, 0 as ShipList 
    from PICKHEAD as p 
    where DATE_REQD = '2017-04-19' 

    union 

    select distinct 0 as OrderList, count(s.PACKSLIP) as Shiplist 
    from SHIPHIST as s 
    where DATE_REQD = '2017-04-19' 
) AS U 

Answer 2

たい、それが行うことができますクロス参加：

select P.Orders + S.Orders as [Total Sales], S.Orders * 100.0/(P.Orders + S.Orders) as [Total Completion Percentage] 
from (
     select count(p.PACKSLIP) as Orders 
     from PICKHEAD as p 
     where DATE_REQD = '2017-04-19' 
    ) as P 
cross join (
     select count(s.PACKSLIP) as Orders 
     from SHIPHIST as s 
     where DATE_REQD = '2017-04-19' 
    ) as S 

Answer 3

代わりCROSS JOINを使用する：

select pOrders + sOrders as sumtotal, 
     (pOrders * 100)/(pOrders + sOrders) 
from 
(
    select count(p.PACKSLIP) as pOrders 
    from PICKHEAD 
    where DATE_REQD = '2017-04-19' 
) as p 
cross join 
(
    select count(s.PACKSLIP) as sOrders 
    from SHIPHIST 
    where DATE_REQD = '2017-04-19' 
) as s