SQLはこれがある</p> <p>を新しい行としてPERSON_2、私は行としてPERSON_1返すようにしたい2人 - を持っているの予約テーブルを持っている

Question

一つのテーブルに二つのフィールドに参加しますが、人のIDを持つ人たちのテーブルに関連します限り私が得た、しかしとして情報

SELECT people.* FROM (
    (select booking.person_1 as id from booking) 
    union ALL 
    (select booking.person_2 as id from booking) 
) as peopleids 
join people on people.id = peopleids.id; 

HERESに私の構造

CREATE TABLE IF NOT EXISTS `booking` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `slot` enum('morning_drive','afternoon_loop','return_drive') NOT NULL, 
    `type` enum('911','vintage_911') NOT NULL, 
    `car` int(11) NOT NULL, 
    `person_1` int(11) DEFAULT NULL, 
    `person_2` int(11) DEFAULT NULL, 
    `dated` date NOT NULL, 
    PRIMARY KEY (`id`) 
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=5 ; 


CREATE TABLE IF NOT EXISTS `people` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `first_name` varchar(50) NOT NULL, 
    `last_name` varchar(50) NOT NULL, 
    `organisation` varchar(100) NOT NULL, 
    `event_date` date NOT NULL, 
    `wave` varchar(20) NOT NULL, 
    PRIMARY KEY (`id`) 
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=9 ; 

私はlike- person.first_name、person.last_name、人物設定の結果を得ることができる方法上の任意のアイデアをご予約に引くdoes notの.orgアニメーション、予約書、人物、車、人物。イム二つのフィールドを持ち、1つのリストに、このに興味がある人のための

更新し、それらを関連付けるためにそれらを持って、私の特定の日付に

がHERESにPHPと私の最後のクエリが引っ張ってvarsの第三のテーブルを結合して苦労また、スロットと第3のテーブルを結合

SELECT peopleids.id, 
     peopleids.car, 
     cars.nr, 
     p.first_name, 
     p.last_name, 
     p.organisation, 
     p.event_date, 
     p.wave 
FROM (SELECT booking.car, booking.person_1 as id FROM booking WHERE booking.dated = '".$date."' AND booking.`slot` = '".$slot."' 
     union ALL SELECT booking.car, booking.person_2 as id FROM booking WHERE booking.dated = '".$date."' AND booking.`slot` = '".$slot."' 
    ) as peopleids 
LEFT JOIN people p ON p.id = peopleids.id LEFT JOIN cars on cars.id = peopleids.car; 

Answer 1

SELECT 
     ag.id, 
     p.first_name, 
     p.last_name, 
     p.organisation, 
     p.event_date, 
     p.wave 
FROM (
     SELECT booking.person_1 as id, booking.Car as car FROM booking 
     union ALL 
     SELECT booking.person_2 as id, booking.Car as car FROM booking 
    ) as ag 
JOIN people p ON people.id = ag.id; 
INNER | LEFT JOIN Cars c ON c.ID = ag.car 

Answer 2

select people.first_name as firstname, 
      people.last_name as lastname, 
      people.organisation, 
      booking.dated, 
      booking.car, 
      booking.slot from booking 
left join people on booking.person_1 = people.id 

ORそれでもサポートが必要な場合...

select people.first_name as firstname, 
      people.last_name as lastname, 
      people.organisation, 
      booking.dated, 
      booking.car, 
      booking.slot 
from booking 
left join people on booking.person_1 = people.id or booking.person_2 = people.id 

チェックはあなた