変換と私はリストの次のネストされたリストを持っているリスト

Question

の複数のネストされたリストに参加：私はそれからに行くとどのように

a = [[[[-79.43402638260521, -1.69184588855758], [-79.4339722432865, -1.691845844583909], [-79.43397178076256, -1.691851284533779], 
    [-79.43395283944169, -1.692053292637794], [-79.43395281911414, -1.33], [-79.43395535750368, -1.692093535418117], 
    [-79.43390444734398, -1.69223087834723], [-79.43390428016939, -1.692231372437897], [-79.43374523144152, -1.692750043925838], 
    [-79.4340256570161, -1.692750271834557], [-79.43402638260521, -1.69184588855758]]], [[[-79.43381375958064, -1.691845715849684], 
    [-79.43312765678151, -1.691845158387183], [-79.4331269307764, -1.692749541273626], [-79.43354270912953, -1.692749879305633], 
    [-79.43364983051107, -1.692588468489809], [-79.4336510738479, -1.692585646334773], [-79.43371548446397, -1.692327269168548], 
    [-79.43380554258165, -1.692094789340216], [-79.43380615195998, -1.692091785860122], [-79.43381375958064, -1.691845715849684]]]] 

を：

a = [[-79.43402638260521, -1.69184588855758], [-79.4339722432865, -1.691845844583909], [-79.43397178076256, -1.691851284533779], 
[-79.43395283944169, -1.692053292637794], [-79.43395281911414, -1.33], [-79.43395535750368, -1.692093535418117], 
[-79.43390444734398, -1.69223087834723], [-79.43390428016939, -1.692231372437897], [-79.43374523144152, -1.692750043925838], 
[-79.4340256570161, -1.692750271834557], [-79.43402638260521, -1.69184588855758], [-79.43381375958064, -1.691845715849684], 
[-79.43312765678151, -1.691845158387183], [-79.4331269307764, -1.692749541273626], [-79.43354270912953, -1.692749879305633], 
[-79.43364983051107, -1.692588468489809], [-79.4336510738479, -1.692585646334773], [-79.43371548446397, -1.692327269168548], 
[-79.43380554258165, -1.692094789340216], [-79.43380615195998, -1.692091785860122], [-79.43381375958064, -1.691845715849684]] 

ので、基本的には、ネストされたリストを削除し、各リストの先頭と最後に二重括弧を付けます。私は大成功せず、次のとittertoolsを試してみた：

flatten = lambda list: [item for sublist in list for item in sublist] 

注：LEN（A）== 2つの

多くの感謝！

[z for x in a for y in x for z in y] 

をし、それを証明するために：あなたが試すことができ

Answer 1

これは仕事です。

a = a[0][0] + a[1][0] 

これは次のように拡張することができ、

a = sum([a[i][0] for i in range(len(a))], []) 

Answer 2

len([y for x in a for y in x]) == 21 

あなたはpprintを使用して、適切にそれを見ることができます。

pprint.pprint(a) 

出力リレー：

[[[[-79.43402638260521, -1.69184588855758], 
    [-79.4339722432865, -1.691845844583909], 
    [-79.43397178076256, -1.691851284533779], 
    [-79.43395283944169, -1.692053292637794], 
    [-79.43395281911414, -1.33], 
    [-79.43395535750368, -1.692093535418117], 
    [-79.43390444734398, -1.69223087834723], 
    [-79.43390428016939, -1.692231372437897], 
    [-79.43374523144152, -1.692750043925838], 
    [-79.4340256570161, -1.692750271834557], 
    [-79.43402638260521, -1.69184588855758]]], 
[[[-79.43381375958064, -1.691845715849684], 
    [-79.43312765678151, -1.691845158387183], 
    [-79.4331269307764, -1.692749541273626], 
    [-79.43354270912953, -1.692749879305633], 
    [-79.43364983051107, -1.692588468489809], 
    [-79.4336510738479, -1.692585646334773], 
    [-79.43371548446397, -1.692327269168548], 
    [-79.43380554258165, -1.692094789340216], 
    [-79.43380615195998, -1.692091785860122], 
    [-79.43381375958064, -1.691845715849684]]]] 

pprint.pprint([z for x in a for y in x for z in y]) 

出力：

[[-79.43402638260521, -1.69184588855758], 
[-79.4339722432865, -1.691845844583909], 
[-79.43397178076256, -1.691851284533779], 
[-79.43395283944169, -1.692053292637794], 
[-79.43395281911414, -1.33], 
[-79.43395535750368, -1.692093535418117], 
[-79.43390444734398, -1.69223087834723], 
[-79.43390428016939, -1.692231372437897], 
[-79.43374523144152, -1.692750043925838], 
[-79.4340256570161, -1.692750271834557], 
[-79.43402638260521, -1.69184588855758], 
[-79.43381375958064, -1.691845715849684], 
[-79.43312765678151, -1.691845158387183], 
[-79.4331269307764, -1.692749541273626], 
[-79.43354270912953, -1.692749879305633], 
[-79.43364983051107, -1.692588468489809], 
[-79.4336510738479, -1.692585646334773], 
[-79.43371548446397, -1.692327269168548], 
[-79.43380554258165, -1.692094789340216], 
[-79.43380615195998, -1.692091785860122], 
[-79.43381375958064, -1.691845715849684]] 

Answer 3

があなたのリストを任意にネストされていないが、あなただけの深い1つのレベルに行くためにしようとしている、あなたは

a = [item for sublist in a for subsublist in sublist for item in subsublist] 

デモのような非常にシンプルなものを選ぶことができると仮定すると、

>>> a = [[[[-79.43402638260521, -1.69184588855758], [-79.4339722432865, -1.691845844583909], [-79.43397178076256, -1.691851284533779], 
[-79.43395283944169, -1.692053292637794], [-79.43395281911414, -1.33], [-79.43395535750368, -1.692093535418117], 
[-79.43390444734398, -1.69223087834723], [-79.43390428016939, -1.692231372437897], [-79.43374523144152, -1.692750043925838], 
[-79.4340256570161, -1.692750271834557], [-79.43402638260521, -1.69184588855758]]], [[[-79.43381375958064, -1.691845715849684], 
[-79.43312765678151, -1.691845158387183], [-79.4331269307764, -1.692749541273626], [-79.43354270912953, -1.692749879305633], 
[-79.43364983051107, -1.692588468489809], [-79.4336510738479, -1.692585646334773], [-79.43371548446397, -1.692327269168548], 
[-79.43380554258165, -1.692094789340216], [-79.43380615195998, -1.692091785860122], [-79.43381375958064, -1.691845715849684]]]] 
>>> desired = [[-79.43402638260521, -1.69184588855758], [-79.4339722432865, -1.691845844583909], [-79.43397178076256, -1.691851284533779], 
[-79.43395283944169, -1.692053292637794], [-79.43395281911414, -1.33], [-79.43395535750368, -1.692093535418117], 
[-79.43390444734398, -1.69223087834723], [-79.43390428016939, -1.692231372437897], [-79.43374523144152, -1.692750043925838], 
[-79.4340256570161, -1.692750271834557], [-79.43402638260521, -1.69184588855758], [-79.43381375958064, -1.691845715849684], 
[-79.43312765678151, -1.691845158387183], [-79.4331269307764, -1.692749541273626], [-79.43354270912953, -1.692749879305633], 
[-79.43364983051107, -1.692588468489809], [-79.4336510738479, -1.692585646334773], [-79.43371548446397, -1.692327269168548], 
[-79.43380554258165, -1.692094789340216], [-79.43380615195998, -1.692091785860122], [-79.43381375958064, -1.691845715849684]] 

>>> a = [item for sublist in a for subsublist in sublist for item in subsublist] 
>>> a == desired 
True 

---

しかし、falsetruで指摘したように、あなたの例では空のレベルの入れ子があります。この場合、解決策はきちんと整理できますas they have shown。

Answer 4

ネストされたリストを反復処理して結合する必要があります。

簡単な方法：

def flatten1(list_of_lists): 
    "Flattens one level of lists." 
    result = [] 
    for sub_list in list_of_lists: 
    result.extend(sub_list) 
    return result 

賢い方法、あなたはリストを追加することができるという事実を利用：

flatten1 = lambda(list_of_lists): sum(list_of_lists, []) 

を今、あなたはa[0] = flatten1(a[0])をすることができます。

Answer 5

itertools.chain.from_iterableを使用する：

list(itertools.chain.from_iterable(xs[0] for xs in a)) 

以上は次のようになりますa[0][0] + a[1][0] + ...（連結挟ん原因リスト作成なし）

---

>>> a = [[[[-79.43402638260521, -1.69184588855758], 
...  [-79.4339722432865, -1.691845844583909], 
...  [-79.43397178076256, -1.691851284533779], 
...  [-79.43395283944169, -1.692053292637794], 
...  [-79.43395281911414, -1.33], 
...  [-79.43395535750368, -1.692093535418117], 
...  [-79.43390444734398, -1.69223087834723], 
...  [-79.43390428016939, -1.692231372437897], 
...  [-79.43374523144152, -1.692750043925838], 
...  [-79.4340256570161, -1.692750271834557], 
...  [-79.43402638260521, -1.69184588855758]]], 
...  [[[-79.43381375958064, -1.691845715849684], 
...  [-79.43312765678151, -1.691845158387183], 
...  [-79.4331269307764, -1.692749541273626], 
...  [-79.43354270912953, -1.692749879305633], 
...  [-79.43364983051107, -1.692588468489809], 
...  [-79.4336510738479, -1.692585646334773], 
...  [-79.43371548446397, -1.692327269168548], 
...  [-79.43380554258165, -1.692094789340216], 
...  [-79.43380615195998, -1.692091785860122], 
...  [-79.43381375958064, -1.691845715849684]]]] 
>>> 
>>> import itertools 
>>> import pprint 
>>> b = list(itertools.chain.from_iterable(xs[0] for xs in a)) 
>>> pprint.pprint(b) 

結果：

[[-79.43402638260521, -1.69184588855758], 
[-79.4339722432865, -1.691845844583909], 
[-79.43397178076256, -1.691851284533779], 
[-79.43395283944169, -1.692053292637794], 
[-79.43395281911414, -1.33], 
[-79.43395535750368, -1.692093535418117], 
[-79.43390444734398, -1.69223087834723], 
[-79.43390428016939, -1.692231372437897], 
[-79.43374523144152, -1.692750043925838], 
[-79.4340256570161, -1.692750271834557], 
[-79.43402638260521, -1.69184588855758], 
[-79.43381375958064, -1.691845715849684], 
[-79.43312765678151, -1.691845158387183], 
[-79.4331269307764, -1.692749541273626], 
[-79.43354270912953, -1.692749879305633], 
[-79.43364983051107, -1.692588468489809], 
[-79.4336510738479, -1.692585646334773], 
[-79.43371548446397, -1.692327269168548], 
[-79.43380554258165, -1.692094789340216], 
[-79.43380615195998, -1.692091785860122], 
[-79.43381375958064, -1.691845715849684]]