-1
私は動的にデータベースから結果を引き出し、
Array (
[0] => Array (
[0] => Array (
[Fruit] => Apple
[Number] => 1
[Date] => 3117-01-41
[supplier] => Store 1
[description] => SAmple text for apple )
[1] => Array (
[Fruit] => Orange
[Number] => 1932
[Date] => 3117-01-41
[supplier] => Store 2
[description] => Sample text for Orange )
[2] => Array (
[Fruit] => Grape
[Number] => 22
[Date] => 3117-01-41
[supplier] => Store Street
[description] => Sample Text for Grape )
[3] => Array (
[Fruit] => Apple
[Number] => 23
[Date] => 3117-01-41
[supplier] => Store 9
[description] => This is text for a second apple)
[4] => Array (
[Fruit] => Apple
[Number] => 49
[Date] => 3117-01-41
[supplier] => Store 007
[description] => This is more text for some apples )
[5] => Array (
[Fruit] => Orange
[Number] => 1
[Date] => 3117-01-41
[supplier] => Store 7
[description] => This is for orange also )
)
)
下に理想的で新しい配列を作成することですように見える配列$ myarrayの、でそれらを置く
そのまま元のままので、$ newArray = $ myArray;
私がしたいことは新しい配列にあります。例えば、 'Fruit'のような別のフィールドを選択すると、別のフィールドが表示されますが、別のフィールドが異なる場合は、新しい配列内に入れ子になった配列を作成します。
<!-- Desired output of $newArray -->
[0] => Array (
[Fruit] => Apple
[Number] => Array
(
[0] => 1
[1] => 23
[2] => 49
)
[Date] => Array
(
[0] => 3117-01-41
[1] => 3117-01-41
[2] => 3117-01-41
)
[supplier] => Array
(
[0] => Store 1
[1] => Store 9
[2] => Store 007
)
[description] => Array
(
[0] => SAmple text for apple
[1] => This is text for a second apple
[2] => This is more text for some apples
) )
[1] => Array (
[Fruit] => Orange
[Number] => Array
(
[0] => 1932
[1] => 1
)
[Date] => Array
(
[0] => 3117-01-41
[1] => 3117-01-41
[2] => 3117-01-41
)
[supplier] => Array
(
[0] => Store 2
[1] => Store 7
)
[description] => Array
(
[0] => Sample text for Orange
[1] => This is for orange also
) )
<!--Grape contents-->
このタスクを解決しようとしたときに書いたコードはどこですか? – arkascha
どこで起動するのかわからない – jumpman8947
まあ、すべての配列要素に対してループを繰り返し作成し、最後の配列に追加する各繰り返しで新しい要素を作成します。そして、あなたは各属性を一つずつ保存します。 – arkascha