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.replaceを使用して初めてPythonに初めて新しくなりました。私は奇妙な問題に遭遇しています。Python .replaceを2回実行しています
url_base = 'http://sfbay.craigslist.org/search/eby/apa'
params = dict(bedrooms=1, is_furnished=1)
rsp = requests.get(url_base, params=params)
# BS4 can quickly parse our text, make sure to tell it that you're giving html
html = bs4(rsp.text, 'html.parser')
# BS makes it easy to look through a document
#print(html.prettify()[:1000])
# BS4 can quickly parse our text, make sure to tell it that you're giving html
html = bs4(rsp.text, 'html.parser')
# BS makes it easy to look through a document
print(html.prettify()[:1000])
# find_all will pull entries that fit your search criteria.
# Note that we have to use brackets to define the `attrs` dictionary
# Because "class" is a special word in python, so we need to give a string.
apts = html.find_all('p', attrs={'class': 'row'})
print(len(apts))
# We can see that there's a consistent structure to a listing.
# There is a 'time', a 'name', a 'housing' field with size/n_brs, etc.
this_appt = apts[15]
print(this_appt.prettify())
# So now we'll pull out a couple of things we might be interested in:
# It looks like "housing" contains size information. We'll pull that.
# Note that `findAll` returns a list, since there's only one entry in
# this HTML, we'll just pull the first item.
size = this_appt.findAll(attrs={'class': 'housing'})[0].text
print(size) , 'this is the size'
def find_size_and_brs(size):
split = size.strip('/- ').split(' - ')
print len(split)
if 'br' in split[0] and 'ft2' in split[0]:
print 'We made it into 1'
n_brs = split[0].replace('br -', '',)
this_size = split[0].replace('ft2 -', '')
elif 'br' in split[0]:
print 'we are in 2'
# It's the n_bedrooms
n_brs = split[0].replace('br', '')
this_size = np.nan
elif 'ft2' in split[0]:
print 'we are in 3'
# It's the size
this_size = split[0].replace('ft2', '')
n_brs = np.nan
print n_brs
print this_size
return float(this_size), float(n_brs)
this_size, n_brs = find_size_and_brs(size)
この出力:それは2倍のデータをプリントアウトする理由
We made it into 1
1
800ft2 -
1br -
800
私は、各データポイントのデータの単一の時間を置き換える、把握することはできません。
思考? ありがとう
「一度データを置き換える」とはどういう意味ですか?具体的には、代わりに出力が期待されますか? – BrenBarn
それは私のためには機能しません。私は 'ValueError:float():1br - 800'の無効なリテラルを取得します。あなたはこのコードを使ってこの結果を得ていますか?多分あなたは別のコードを実行しますか? – furas
@BrenBarn私は1 800の出力を得るために探しています。基本的にはbrまたはft2なしのデータ。これは理にかなっていますか? –