python keyerrorの間違い

Question

私は以前この質問を受けていましたが、解決策を得られなかったので、誰も私と同じ問題が発生したようにオンラインで検索しませんでした。あるいは、ジェソンについて何か間違っていますか？ 誰かが私を助けることができますか？私はPythonの初心者です。 多くの感謝！ KeyError例外：「コンテンツ」

# -*- coding:utf-8 -*- 
import requests 
import time 
import random 
import xlwt 
import json 

def post_request(url=None, para={}, headers={}): 
    print 'Downloading: ' + str(para['pn']) 
    req = requests.post(url, data=para, headers=headers) 
    return req 

if __name__ == '__main__': 
    url = 'https://www.lagou.com/jobs/positionAjax.json?needAddtionalResult=false&isSchoolJob=0' 
    headers = { 
     'Host':'www.lagou.com', 
     'Referer':'https://www.lagou.com/jobs/list_%E6%95%B0%E6%8D%AE%E5%88%86%E6%9E%90?labelWords=&fromSearch=true&suginput', 
     'User-Agent':'Mozilla/5.0 (Linux; Android 6.0; Nexus 5 Build/MRA58N) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.96 Mobile Safari/537.36' 
    } 

    pn = 1 
    end = 31 
    for x in range(pn, end, 1): 
     para = { 
      'first': 'true', 
      'kd': 'Python', 
      'pn': pn 
     } 
     req = post_request(url, para, headers) 
     path = 'd://PyCharmProject//lagou_scraping//Python_search_result//' 
     f = open(path + para['kd'] + '-' + str(para['pn']) + '.json', 'wb') 
     f.write(req.content) 
     f.close() 
     time.sleep(random.randint(3, 8)) 
     pn = pn + 1 
def read_json(path): 
    f = open(path) 
    dictory = json.load(f, encoding='utf-8') 
    return dictory 

if __name__ == '__main__': 
    xls = xlwt.Workbook() 
    sheet = xls.add_sheet('native') 
    sheet.write(0, 0, 'positionName') 
    sheet.write(0, 1, 'salary') 
    sheet.write(0, 2, 'education') 
    sheet.write(0, 3, 'workYear') 
    sheet.write(0, 4, 'city') 
    sheet.write(0, 5, 'companyShortName') 
    sheet.write(0, 6, 'companySize') 
    sheet.write(0, 7, 'financeStage') 
    sheet.write(0, 8, 'industryField') 
    sheet.write(0, 9, 'jobNature') 
    sheet.write(0, 10, 'companyLogo') 

    sheetPosition = {'row':1, 'col':0} 
    pn = 1 
    for x in range(pn, 31, 1): 
     path = 'd://PyCharmProject//lagou_scraping//Python_search_result//Python-' + str(pn) + '.json' 
     dictory = read_json(path) 
     row = sheetPosition['row'] 
     col = sheetPosition['col'] 
     pn = pn + 1 
     for x in dictory['content']['positionResult']['result']: 
      sheet.write(row, col, x['positionName']) # 0 
      col = col + 1 
      sheet.write(row, col, x['salary']) # 1 
      col = col + 1 
      sheet.write(row, col, x['education']) # 2 
      col = col + 1 
      sheet.write(row, col, x['workYear']) # 3 
      col = col + 1 
      sheet.write(row, col, x['city']) # 4 
      col = col + 1 
      sheet.write(row, col, x['companyShortName']) # 5 
      col = col + 1 
      sheet.write(row, col, x['companySize']) # 6 
      col = col + 1 
      sheet.write(row, col, x['financeStage']) # 7 
      col = col + 1 
      sheet.write(row, col, x['industryField']) # 8 
      col = col + 1 
      sheet.write(row, col, x['jobNature']) # 9 
      col = col + 1 
      sheet.write(row, col, x['companyLogo']) # 10 
      col = col + 1 

      col = 0 
      row = row + 1 
      sheetPosition = {'row': row, 'col': col} 
    xls.save('d://PyCharmProject//lagou_scraping//lagou_python.xls') 

Answer 1

はあなたのエラーはここから来ているように思える：

f = open(path + para['kd'] + '-' + str(para['pn']) + '.json', 'wb') 
    f.write(req.content) # <-- Here is the probable error. 
    f.close() 

おそらく、あなたが最初のステータスコードをチェックしたり、 キャッチエラーにブロックを試みる必要があります。

#using status code 200 
#some server may return different status code 
#other than 200, check how the server return on success 
if(req.status_code == 200): 
    #now you're ok to resume with your code above 
else: 
    #since you're in the for loop, skip this iteration 
    pass 

これが役立つことを願っています。