2日間の休日を除く

Question

私はインターネット上で検索しましたが、最後にこのコードを Weekend Exclusionに検索しました。

OR

function calcBusinessDays(dDate1, dDate2) { // input given as Date objects 
    var iWeeks, iDateDiff, iAdjust = 0; 
    if (dDate2 < dDate1) return -1; // error code if dates transposed 
    var iWeekday1 = dDate1.getDay(); // day of week 
    var iWeekday2 = dDate2.getDay(); 
    iWeekday1 = (iWeekday1 == 0) ? 7 : iWeekday1; // change Sunday from 0 to 7 
    iWeekday2 = (iWeekday2 == 0) ? 7 : iWeekday2; 
    if ((iWeekday1 > 5) && (iWeekday2 > 5)) iAdjust = 1; // adjustment if both days on weekend 
    iWeekday1 = (iWeekday1 > 5) ? 5 : iWeekday1; // only count weekdays 
    iWeekday2 = (iWeekday2 > 5) ? 5 : iWeekday2; 

    // calculate differnece in weeks (1000mS * 60sec * 60min * 24hrs * 7 days = 604800000) 
    iWeeks = Math.floor((dDate2.getTime() - dDate1.getTime())/604800000) 

    if (iWeekday1 <= iWeekday2) { 
     iDateDiff = (iWeeks * 5) + (iWeekday2 - iWeekday1) 
    } else { 
     iDateDiff = ((iWeeks + 1) * 5) - (iWeekday1 - iWeekday2) 
    } 

    iDateDiff -= iAdjust // take into account both days on weekend 

    return (iDateDiff + 1); // add 1 because dates are inclusive 
    } 

私は休日を除外するためにコードを追加する方法は考えています。私は休日を格納する配列を作成する必要があることを理解しますが、その後、私はその時点で立ち往生しています。私はあなたの助けが必要です、大変感謝します。

Answer 1

休日の配列をループして日付が範囲内にあるかどうかをチェックし、休日が土曜日か日曜日かをチェックします。その場合は、既にカウントされています。以下は変更された例です。

function calcBusinessDays(dDate1, dDate2, holidays) { // input given as Date objects 
    var iWeeks, iDateDiff, iAdjust = 0, i; 
    if (dDate2 < dDate1) return -1; // error code if dates transposed 
    var iWeekday1 = dDate1.getDay(); // day of week 
    var iWeekday2 = dDate2.getDay(); 
    iWeekday1 = (iWeekday1 == 0) ? 7 : iWeekday1; // change Sunday from 0 to 7 
    iWeekday2 = (iWeekday2 == 0) ? 7 : iWeekday2; 
    if ((iWeekday1 > 5) && (iWeekday2 > 5)) iAdjust = 1; // adjustment if both days on weekend 
    iWeekday1 = (iWeekday1 > 5) ? 5 : iWeekday1; // only count weekdays 
    iWeekday2 = (iWeekday2 > 5) ? 5 : iWeekday2; 

    // calculate differnece in weeks (1000mS * 60sec * 60min * 24hrs * 7 days = 604800000) 
    iWeeks = Math.floor((dDate2.getTime() - dDate1.getTime())/604800000) 

    if (iWeekday1 <= iWeekday2) { 
     iDateDiff = (iWeeks * 5) + (iWeekday2 - iWeekday1) 
    } else { 
     iDateDiff = ((iWeeks + 1) * 5) - (iWeekday1 - iWeekday2) 
    } 

    iDateDiff -= iAdjust; // take into account both days on weekend 

    for(i = 0; i < holidays.length; i++) { 
     if(holidays[i] >= dDate1 && holidays[i] <= dDate2 && holidays[i].getDay() != 0 && holidays[i].getDay() != 6) { 
     iDateDiff--; 
     } 
    } 

    return (iDateDiff + 1); // add 1 because dates are inclusive 
    } 

var holidays = [ new Date(2017, 5, 2), new Date(2017, 5, 3), new Date(2017, 5, 4), new Date(2017, 5, 5) ]; 

calcBusinessDays(new Date(2017,1,1), new Date(), holidays); 
// returns 93