このmysqlクエリを修正して勝率を表示するにはどうすればよいですか？

Question

以下このクエリ：

SELECT member, count(*) Wins 
FROM (SELECT player2_name as member from results 
WHERE player1_id = 2 AND player1_result = 'W' AND community_id = 16 
UNION ALL SELECT player1_name FROM results WHERE player2_id = 2 
AND player2_result = 'W' AND community_id = 16) AS T 
group by member ORDER BY Wins DESC 

は、次のような結果が生成されます。データをより便利にするために

+---------+-----------+ 
| member | Wins | 
+---------+-----------+ 
| Player 1|  4  | 
| Player 2|  3  | 
| Player 3|  3  | 
+---------+-------------+ 

（各プレイヤーがゲームの異なる数を果たしていることのように）私が表示したいです余分な列の '勝率'。

- >これは、各プレイヤーがプレイしたゲームの数に基づいています。私は期待していた

+---------+-----------+---------------+---------+ | member | Wins | Games Played | Win % | +---------+-----------+---------------+---------+ | Player 1| 4 | 8 | 0.50 | | Player 2| 3 | 3 | 1.00 | | Player 3| 3 | 5 | 0.60 | +---------+-----------+---------------+---------+

： - ％を出力すると、MySQLの中で直接可能でないならば、小数点以下は、どのように私は以下のように出力を生成するために、私の既存のクエリを修正することができ0.76

すなわち罰金だろう

SELECT GamesPlayed FROM (SELECT player1_name as member from results 
WHERE player1_id = 2 AND community_id = 16 
UNION ALL SELECT player2_name FROM results WHERE player2_id = 2 
AND community_id = 16) AS GP 

して、1行目に：ただの線に沿って何かを追加する

SELECT member, count(*) Wins, round(sum(wins/GamesPlayed(1),2) WinPercentage 

しかし、それは私がそれがどのように動作するかを見て非常に大まかな希望を推測する。

最新のテストデータ：このような

Answer 1

何か？

更新クエリ

SELECT 
    T.member 
    , count(*) Wins 
    , total.gamesPlayed 
    , count(*)/total.gamesPlayed as winPercentage 
FROM 
    (
     SELECT 
      player2_name as member 
     from results 
     WHERE 
      player1_id = 2 
      AND player1_result = 'W' 
      AND community_id = 16 
     UNION ALL 
     SELECT 
      player1_name 
     FROM results 
      WHERE player2_id = 2 
      AND player2_result = 'W' 
      AND community_id = 16 
    ) AS T 
    , (
      select 
       u.member 
       , sum(u.gamesPlayed) as gamesPlayed 
      from 
       (
        select 
         player2_name as member 
         , count(*) gamesPlayed 
        from results 
        where 
         player1_id = 2 
         AND community_id = 16 
        group by player2_name 
        union 
        select 
         player1_name as member 
         , count(*) gamesPlayed 
        from results 
        where 
         player2_id = 2 
         AND community_id = 16 
        group by player2_name 
       ) as u /* union of two */ 
      group by member 
    ) as total 
where 
    T.member = total.member 
group by T.member 
ORDER BY Wins DESC