特定の期間の合計とグループ化の方法

Question

30分のデータがあり、現在の午前2時から翌日02時に曜日と時間を合計したい場合、どうすればいいですか？ ：最後に

create table test (code varchar2(50), hour number, daytime date); 

insert into test (code, hour, daytime) values ('K11','0.5','23-Feb-17') 
insert into test (code, hour, daytime) values ('K11','0.5','23-02-17 00:30') 
insert into test (code, hour, daytime) values ('K11','0.5','23-02-17 01:00') 
insert into test (code, hour, daytime) values ('K11','0.5','23-02-17 01:30') 
insert into test (code, hour, daytime) values ('K11','0.5','23-02-17 02:00') 
insert into test (code, hour, daytime) values ('K11','0.5','23-02-17 02:30') 
insert into test (code, hour, daytime) values ('K11','0.5','24-Feb-17') 
insert into test (code, hour, daytime) values ('K11','0.5','24-02-17 00:30') 
insert into test (code, hour, daytime) values ('K11','0.5','24-02-17 01:00') 
insert into test (code, hour, daytime) values ('K11','0.5','24-02-17 01:30') 
insert into test (code, hour, daytime) values ('K11','0.5','24-02-17 02:00') 
insert into test (code, hour, daytime) values ('K11','0.5','24-02-17 02:30') 
insert into test (code, hour, daytime) values ('K12','0.5','23-Feb-17') 
insert into test (code, hour, daytime) values ('K12','0.5','23-02-17 00:30') 
insert into test (code, hour, daytime) values ('K12','0.5','23-02-17 01:00') 
insert into test (code, hour, daytime) values ('K12','0.5','23-02-17 01:30') 
insert into test (code, hour, daytime) values ('K12','0.5','23-02-17 02:00') 
insert into test (code, hour, daytime) values ('K12','0.5','23-02-17 02:30') 
insert into test (code, hour, daytime) values ('K12','0.5','24-Feb-17') 
insert into test (code, hour, daytime) values ('K12','0.5','24-02-17 00:30') 
insert into test (code, hour, daytime) values ('K12','0.5','24-02-17 01:00') 
insert into test (code, hour, daytime) values ('K12','0.5','24-02-17 01:30') 
insert into test (code, hour, daytime) values ('K12','0.5','24-02-17 02:00') 
insert into test (code, hour, daytime) values ('K12','0.5','24-02-17 02:30') 

私は、データを次取得したいのですが：

'K11',3,'23-02-17' 
'K12',3,'23-02-17' 

だから、 '、（ 'K11'、 '0.5' からK11のために例えば23-02-17の時間を合計します02:00 '）から（' K11 '、' 0.5 '、' 24-02-17 01:00 '）

Answer 1

これを行うには、 2時間。

select trunc(date - 2/24) as dte, sum(hours) 
from t 
group by trunc(date - 2/24) 
order by dte; 

Oracleは今interval構文をサポートしていますので、あなたもDすることができます：

select trunc(date - interval 2 hour) as dte, sum(hours) 
from t 
group by trunc(date - interval 2 hour) 
order by dte;