-4
私のcin >> OneDecision;
はスキップされ続けます。My cin >>がスキップ/無視されています
私はcin.getline(OneDecision, 40)
を試しました。それは動作しません、そして、なぜ私は知らない。そして、私がそれを修正しない限り、私はゲームで実際に続けることはできません。
これはクラス割り当てのためのもので、短いテキストベースのホラーゲームになります。もし私が助けを得ることができれば、それはうれしいでしょう。私は素人です、慈悲を持ってください。あなたが変更する必要が
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <windows.h>
#include <iomanip>
#include <limits>
using namespace std;
int main()
{
char player1 [40],
char fear [40];
char friend1 [40];
char friend2 [40];
int start;
char option [40], option2 [40], option3 [40], option4 [40];
char OneDecision [40], OneDecision2 [40];
cout << "Hey.... what's your name?\n";
cin.get(player1, 40);
cout<< "Well, " << player1 << ". What is your biggest fear?\n";
cin >> fear ;
cout <<"Name one friend.\n";
cin >> friend1;
cout << "Name another friend... or make one up if you have none.\n";
cin >> friend2;
cout<< "Are you ready to play?\n 1. Yes or 2. No.\n";
cin >> start ;
if (start == 1)
{
cout << "You'll later regret it...\n You have entered HORROR HOUSE.";
}
else if (start == 2)
{
cout << "I don't blame you. Why the hell would you want to enter a horror house to be honest...\n\n\n\n";
cout << " END GAME.";
}
Sleep(2500);
system("cls");
cout<< "You, " << friend1 << " and " << friend2 << " are staying at the mansion " << friend1 << "'s family recently \nbought.";
cout << "It's night, and you are in your room sleeping.\nWhen you here a loud noise, a thump.\nYou get out of bed, and look around to see if something fell.\n";
cout << "The door you though you closed was left open, and but other than that nothing is wrong.\n\n\n\n\n";
Sleep (12000);
cout << " But then you hear a horrible scream from outside.\n\n";
cout << " Run to window and see? Or Run to " << friend1 << "'s room?\n";
cin.get(option, 40);
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n'); // The program terminates at this line, I've tried other ways of saying for it to ignore the next line but none of them worked, this was the last thing I tried.
if (string(option) == "run to window" || string(option) == "window")
{
cout << " \n You run to the window and see " << friend1 << " laying dead on the ground outside.\n";
cout << " Go downstairs and out the house toward" << friend1 << "?\n Or run to " << friend2 << "'s room to wake them up." ;
cin.get(OneDecision, 40);
if (OneDecision == "go downstairs")
{
cout << "You are running downstairs. You run out of the house, and search you're backyard for" << friend1 << ", but , you can't find their body.";
}
return 0;
ご入力のいずれかがスペースを持っている、あなたはgetline'上の '使用する必要がある場合それらの入力のいずれか。 – NathanOliver
そして、あなたの次の問題の答えは、あなたが 'getline'を使い始めた後に起こります:http://stackoverflow.com/a/21567292/3410396 –
'option ==" run to window "は'option'は' std :: string'です。 Cスタイルのchar配列では 'strcmp'を使う必要があります。 –