XDocument/xNamespace

Question

<AllscriptsMessageEnvelope xmlns="http://Allscripts.com/UAI/Schemas/2010/02/15" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ns4="urn:Allscripts:Hub:PatientMsg" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> 
    <MessageDispatchHeader> 
    <ID xmlns="">229dd2a9-9c6c-49c5-aebe-3210c7b00df2 </ID> 
    <Noun xmlns="">Message</Noun> 
    <Verb xmlns="">Received</Verb> 
    <TimeStamp xmlns="">2011-06-23T22:06:52</TimeStamp> 
    <Description xmlns="">Rx Hub Message</Description> 
    <Originator xmlns=""> 
     <OriginatorName /> 
    </Originator> 
    <Destination xmlns=""> 
     <SendToName /> 
    </Destination> 
    </MessageDispatchHeader> 
    <EntityContext /> 
    <MessageContent xmlns=""> 
    <ns4:MessageProcessed> 
     <ns4:ReplyToMessageID>0906b2b2-e690-459f-82f0-82d6c33e6e03</ns4:ReplyToMessageID> 
     <ns4:TransportStatus>Success</ns4:TransportStatus> 
     <ns4:ApplicationStatus>Success</ns4:ApplicationStatus> 
     <ns4:Datetime>2011-06-23T22:06:52</ns4:Datetime> 
     <ns4:Comment>Message Accepted by Rx Hub.</ns4:Comment> 
     <ns4:AdditionalDetails> 
     <ns4:AdditionalDetail>Delivered using RxPrescriptionService WCF Service</ns4:AdditionalDetail> 
     </ns4:AdditionalDetails> 
    </ns4:MessageProcessed> 
    </MessageContent> 
</AllscriptsMessageEnvelope> 

<ns4:ApplicationStatus>Success</ns4:ApplicationStatus>の値を取得するにはどうすればよいですか？

Answer 1

var xdocument = XDocument.Load(@"C:\1.xml"); 
var result = xdocument.Descendants(XName.Get("ApplicationStatus", "urn:Allscripts:Hub:PatientMsg")).First().Value; 

または

var result = xdocument.XPathSelectElement("//ns4:ApplicationStatus", xdocument.Root.CreateNavigator()).Value; 

Answer 2

XNamespace ns4 = "urn:Allscripts:Hub:PatientMsg"; 
XDocument doc = XDocument.Load("yourFileName.xml"); 
string applicationStatusValue = doc.Root.Element("MessageContent") 
             .Element(ns4 + "MessageProcessed") 
             .Element(ns4 + "ApplicationStatus") 
             .Value;