ハングマンゲームの出力エラー

Question

ハングマンゲームを構成する2つの関数を記述する必要があります。私はコードを持っていますが、エラーが発生し続け、コードが完全に実行されないため、コードが正しいかどうかわかりません。これは私が持っているコードです。ここでは何が起こっている

Welcome to the Hangman game! 
I am thinking of a word that is 1 letters! 
You have 8 guesses left 
Available letters: abcdefghijklmnopqrstuvwxyz 
Please guess a letter: c 
Traceback (most recent call last): 

File "submission.py", line 81, in hangman 
    if isWordGuessed(secretWord, lettersGuessed) == "True": 
File "simple_grade_hangman.py", line 107, in isWordGuessed 
    if letter not in lettersGuessed: 
TypeError: argument of type 'NoneType' is not iterable 

：

def isWordGuessed(secretWord, lettersGuessed): 
    ''' 
    secretWord: string, the word the user is guessing 
    lettersGuessed: list, what letters have been guessed so far 
    returns: boolean, True if all the letters of secretWord are in lettersGuessed; 
     False otherwise 
    ''' 
    if lettersGuessed == []: 
     return False 
    else: 
     for i in secretWord: 
      if i not in lettersGuessed: 
       return False 
     else: 
      if i == secretWord[-1]: 
       return True 

def getGuessedWord(secretWord, lettersGuessed): 
    lst= '' 
    for e in secretWord: 
     if e in lettersGuessed: 
      lst += e 
     else: 
      lst += '_' 
    return lst 

def getAvailableLetters(lettersGuessed): 
    ''' 
    lettersGuessed: list, what letters have been guessed so far 
    returns: string, comprised of letters that represents what letters have not 
     yet been guessed. 
    ''' 
    Alletters = string.ascii_lowercase 
    result = list(Alletters) 
    for i in lettersGuessed: 
     if i in result: 
      result.remove(i) 
    transtring = ''.join(result) 
    return transtring 

def hangman(secretWord): 
    ''' 
    secretWord: string, the secret word to guess. 

    Starts up an interactive game of Hangman. 

    * At the start of the game, let the user know how many 
     letters the secretWord contains. 

    * Ask the user to supply one guess (i.e. letter) per round. 

    * The user should receive feedback immediately after each guess 
     about whether their guess appears in the computers word. 

    * After each round, you should also display to the user the 
     partially guessed word so far, as well as letters that the 
     user has not yet guessed. 

    Follows the other limitations detailed in the problem write-up. 
    ''' 
    print("Welcome to the Hangman game!") 
    print("I am thinking of a word that is " + str(len(secretWord)) + " letters!") 
    guesses = 8  
    lettersGuessed = [] 
    Alletters = string.ascii_lowercase  
    while guesses > 0:  
     print("You have " + str(guesses) + " guesses left") 
     print("Available letters: " + str(Alletters)) 
     letters = input("Please guess a letter: ") 
     if type(letters) != str: 
      print("Invalid input! please enter one letter!") 
     else: 
      letterslower = letters.lower()  
      lettersGuessed = lettersGuessed.append(letterslower) 
      if letterslower not in Alletters: 
       print("Opps! you have already guessed that letter: " + getGuessedWord(secretWord, lettersGuessed)) 
      else: 
       if isWordGuessed(secretWord, lettersGuessed) == "True": 
        print("Congradualations, you won!") 
       else: 
        print("Good guess: " + getGuessedWord(secretWord, lettersGuessed)) 
        guesses -= 1 
        Alletters = getAvailableLetters(lettersGuessed) 
    print("You have ran out of guess, the word is " + str(secretWord)) 

これは出力（エラーは黄色である）でしょうか？

Answer 1

あなたのエラーは、このラインから茎：

lettersGuessed = lettersGuessed.append(letterslower) 

これは、インプレースリストを変更し、Noneを返します。変更されたリストへの参照を返すという前提のもとで操作していますが、そうではありません。

だから、あなたはlettersGuessedがNoneあるとNoneがin式のターゲットとして使用することができないため、エラーが発生します、isWordGuessedとif i not in lettersGuessedが実行された関数にパラメータとして渡すとき。

は単にappendに変更し、変更内容が保存されています

lettersGuessed.append(letterslower) 

また、str（"True"）に対してブール（True）を比較すると、あなたに誤った結果が得られます：

代わり

>>> True == 'True' 
False 

、 isWordGuessedはブール値を返しますので、if節の戻り値を直接使用してください：

if isWordGuessed(secretWord, lettersGuessed):