1
Djangoで "Upload Progress Bar"を実装しようとしています。続きDjangoのAJAXを使用して進行中のアップロードステータスをHTMLに戻す際に直面する問題
は、テンプレート・ファイル内の私のコードです：後
{% extends "index_base.html" %}
{% block content %}
<script src="/media/js/functions.js" type="text/javascript"></script>
<script src="/media/js/jquery.js" type="text/javascript"> </script>
<script type="text/javascript">
var xhrObject1;
var xhrObject2;
function createXMLHttpObject()
{
var xhrObject; // The variable that makes Ajax possible!
try
{
xhrObject = new XMLHttpRequest();
}
catch (e)
{
try{
xhrObject = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e){
try {
xhrObject = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {
xhrObject = null;
}
}
}
return xhrObject;
}
function ajaxFunction()
{
xhrObject1 = createXMLHttpObject();
if (xhrObject1 == null)
{
alert("Your browser does not support ajax.");
return;
}
xhrObject1.onreadystatechange = function(){
if(xhrObject1.readyState == 4){
document.getElementById("targetDiv").innerHTML = xhrObject1.responseText;
}
else
{
xhrObject2 = createXMLHttpObject();
xhrObject2.onreadystatechange = function(){
if(xhrObject2.readyState == 4){
document.getElementById("targetDiv").innerHTML = xhrObject2.responseText;
}
else
{
document.getElementById("targetDiv").innerHTML = "getting progress...";
}
}
xhrObject2.open("GET", "/upload_progress.psp", true);
xhrObject2.send(null);
}
}
var arrFiles = document.getElementById('id_file');
var fileToUpload = arrFiles.files[0];
xhrObject1.open("POST", "/upload.psp/", true);
xhrObject1.send(fileToUpload);
}
function submitForm()
{
document.forms["myform"].submit();
ajaxFunction();
return false;
}
</script>
<div id="main_container">
{% include "includes/nav.html" %}
<!------- Main Contents ---------->
<div id="contents_holder">
<div id="contents">
<div id="c_banner">
<span class="main_title">Upload File</span>
</div>
<div id="targetDiv" > </div>
<div id="setting">
<form name="myform" id="myform" action="/upload.psp/" method="post" enctype="multipart/form-data">
<h2>Upload File</h2></br>
<p>{{ form.file.label_tag }} {{ form.file }}</p></br>
<input type="button" value="Upload" name="uploadButton" onclick="javascript:return submitForm();"/>
<input type="button" value="Cancel" name="cancelUploadButton" onclick ="cancelUploadClicked()"/>
<input type="hidden" value="title" name="title" id="title" />
</form>
</div>
</div>
</div>
</div>
{% endblock %}
はviews.py内の私の二つの機能です：
@condition(etag_func=None)
def upload(request):
if request.method == 'POST':
form = UploadFileForm(request.POST, request.FILES)
if form.is_valid():
#handle_uploaded_file(request.FILES['file'])
f = request.FILES['file']
filename = "/host_lighttpd/var/www/htdocs/satellite/static/Data/" + f.name
destination = open(filename, 'wb+')
for chunk in f.chunks():
destination.write(chunk)
#yield chunk
request.session['uploaded'] += chunk
destination.close()
return render_to_response('uploadsuccess.html')
else:
form = UploadFileForm()
return render_to_response('upload.html', {'form': form})
def upload_progress(request):
#uploaded = request.session['uploaded']
return HttpResponse("Upload progress function...")
#return HttpResponse(uploaded)
私の問題は、私は戻っへのアップロードのステータスを返すことができる方法です 2番目のajax呼び出し（GETメソッド）。最終的にhtml内の に更新されます。
進行中のアップロードステータスを返す方法がわかりません。
ご協力いただければ幸いです。前もって感謝します。